addedge

2-sat, split into six points.#include #include#include#include#include#includeusing namespacestd;Const intmaxn=60000+Ten;intT,n,m;stackint>S;vectorint>G[maxn];vectorint>FG[MAXN];intBELONG[MAXN];intFLAG[MAXN];intBlock;intX[MAXN];voidinit () {

I have read 2-SAT papers over the past few days, and I have also made some related questions. The so-called 2-SAT is A pair of contradictions, that is, they cannot get together, such as family A and B. Family A has a0 and a1, and family B has b0 and

http://acm.hdu.edu.cn/showproblem.php?pid=4115Title Description:Bob, and Alice two in the N-round scissors-stone cloth, known Bob N-wheel out of the case, for Alice given the M-group limit, as long as each round Alice did not lose, after the N-round

This blog post for the migration, written on May 16, 2015, does not represent my current views and views. Original address: http://blog.sina.com.cn/s/blog_6022c4720102w0d8.html1. Prefacefirst, a concept-the minimum cut. What is the minimum cut? On

Min. cut.s even for everyone (volume: Choose the pleasure of science); everyone even t (capacity: Choose the pleasure of science).For each group (x, Y, W) x and y add pleasure W, new node V,v x (INF), V-connected Y (INF), S even v (w)For each group (

If a person does not have an outbound vertex, he or she can jump to any vertex. The minimum number of jumps makes it necessary to walk all the edges. Question: The smallest stream with the upper and lower bounds. [Cpp]# Include # Include # Include #

Catch the ThevesTime limit:5000/2000 MS (java/others) Memory limit:65768/32768 K (java/others)Total submission (s): 1640 Accepted Submission (s): 514Problem Descriptiona Group of thieves is approaching a museum in the country of Zjsxzy,now they be

Min. cut ... The two-point staining then turns the color of the dots to the Yuanhui of the opposite. And then you can do it.A point (x, y):S->id (x, y) (return), id (x, y)->t (cost), ID (i,j) &&id (neighboring node)->newid (I,j) (+oo), NewId

For the first time in a few monthsCodeI don't know how to write the largest naked stream: rqnoj 194: Student transportation,AlgorithmThere are too many definitions, analyses, and proofs in the introduction. I didn't quite understand them at the

To define a node class://一个节点class Vertex{ char label; boolean wasVisited; publicVertex(char label){ this.label = label; false; }}Figure:Class graph{Private Final intMax_verts = -;PrivateVertex vertexlist[];//Node list

Question:Here We Go (relians) AgainTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission (s): 360 Accepted Submission (s): 204 Problem DescriptionThe Gorelians are a warlike race that travel the universe

The most powerful closed sub-graph. The building is ingenious.Most powerful closed sub-graphs:#pragmaComment (linker, "/stack:1024000000,1024000000")#include#include#include#include#include#include#includeSet>#include#include#includeusing

To build a dual graph, the shortest path is the maximum flowThe surface of the connection s,t is the new S, the periphery is the new T,Directed graph connecting edge direction depending on the situation#include #include#include#defineLL Long

1#include 2#include 3#include 4 using namespacestd;5 structedge{6 intto, cost;7EdgeintTintc): to (t), cost (c) {8 //Empty Body9 }Ten }; One voidAddedge (vectorint> > &G,vector &edgelist,int from,intTo,intCost ) { AEdge E =Edge

poj3683Title: There are several activities that can be selected in one of two time periods, asking for an allocation scheme that makes all activities non-conflicting.Idea: 2set bare topic, sset need to do a strong unicom component decomposition, and

Check whether a given graph is bipartite or notA bipartite graph is a graph whose vertices can being divided into a independent sets, u and V such that every edge (U, V) Either connects a vertex from U-V or a vertex from V to U. In other words, for

Must pay attention to the INF to open very large. Otherwise... Hey, heh.Because the traffic may cross, then b1,b2 to run again.1 A is cool.#include #include#include#include#include#defineMAXV 650#defineMaxe 250500#defineINF 9999999999999999using

Topic Connection: BZOJ-3218Problem analysisThe topic requires that n Dianran be black or white, then we can convert to a minimal cut model.We stipulate that a point I finally belongs to the S-set expression dyed black, which belongs to the T-set to

CopyCode The Code is as follows: # include # Include # Include Using namespace STD; Class graph {Int vertexnum;List * adjacents;Public:Graph (INT _ vertexnum ){Vertexnum = _ vertexnum;Adjacents = new list [vertexnum];}Void findindegree (int

Node Capacity: Break it up and write it.---------------------------------------------------------------#include #include #include using namespace std;#define CHK (x, y) (x >= 0 && x = 0 && y const int MAXN = 10000;const int MAXM = 2900;int H[MAXN],